console - Command line 7Zip to extract file by specified result path

06
2014-04
  • SerG

    Is it possible to make 7Zip extract one file by name from archive to specified full path (including new filename)?

    I've found only:

    7zip e <archive> -o<resultDirectory> <filemask>

    But it's not what I need.

    • Answers
  • Axel Kemper

    You can use the -so option to write the data to stdout and redirect to your target file:

    Example:

    7z e -so xxxx.7z > yyy.txt

    The commandline help of version 9.22 beta:

    7-Zip [64] 9.22 beta  Copyright (c) 1999-2011 Igor Pavlov  2011-04-18

Usage: 7z <command> [<switches>...] <archive_name> [<file_names>...]
       [<@listfiles...>]

<Commands>
  a: Add files to archive
  b: Benchmark
  d: Delete files from archive
  e: Extract files from archive (without using directory names)
  l: List contents of archive
  t: Test integrity of archive
  u: Update files to archive
  x: eXtract files with full paths
<Switches>
  -ai[r[-|0]]{@listfile|!wildcard}: Include archives
  -ax[r[-|0]]{@listfile|!wildcard}: eXclude archives
  -bd: Disable percentage indicator
  -i[r[-|0]]{@listfile|!wildcard}: Include filenames
  -m{Parameters}: set compression Method
  -o{Directory}: set Output directory
  -p{Password}: set Password
  -r[-|0]: Recurse subdirectories
  -scs{UTF-8 | WIN | DOS}: set charset for list files
  -sfx[{name}]: Create SFX archive
  -si[{name}]: read data from stdin
  -slt: show technical information for l (List) command
  -so: write data to stdout
  -ssc[-]: set sensitive case mode
  -ssw: compress shared files
  -t{Type}: Set type of archive
  -u[-][p#][q#][r#][x#][y#][z#][!newArchiveName]: Update options
  -v{Size}[b|k|m|g]: Create volumes
  -w[{path}]: assign Work directory. Empty path means a temporary directory
  -x[r[-|0]]]{@listfile|!wildcard}: eXclude filenames
  -y: assume Yes on all queries

    More recent alpha versions (9.30) also do not allow to specify a target filename as direct parameter without redirection.


    • Related Question

    7 zip - 7Zip - Command Line : Exclude folder(s) by wildcard pattern?
  • Yoopergeek

    Any idea how to exclude a wild-carded path(s) from a command-line 7zip command?

    I'm doing something this: 

    7z.exe a -t7z archive.7z FolderToArchive\ -mx0

    and would like to exclude any \bin*.* or \obj*.* folders found underneath "FolderToArchive". To exclude files you can use the -x parameter. The help file gives this example for using -x:

    7z a -tzip archive.zip *.txt -x!temp.*

    That's great for excluding a file. But, again, I would like to exclude a wildcard-specified folder. Under my "FolderToArchive" there are multiple folders, under those folders there may or may not be "bin\" and "obj\" folders. I would like to not include these in the archive.

    I've tried patterns like:

    -x!bin* -x!bin*.* -x!\bin* -x!\bin*.* -x!\bin\* -x!\bin\*.*

    None seem to exclude. Is this simply a limitation of 7zip?


    • Related Answers
  • heavyd

    To exclude the bin and obj folders recursively you can use the command:

    7z.exe a -t7z archive.7z FolderToArchive\ -mx0 -xr!bin -xr!obj
  • user304204

    To avoid bug, use -r or -xr carefully.

    suppose you have directories like:

    .\path1\path2\bin
.\path1\path2\src
.\path3\path4\path5\bin
.\path3\path4\path5\src

    and run the command:

    7z a -t7z archive.7z .\path1\path2 .\path3\path4\path5 -xr!bin

    what you got in archive.7z: .\path2\src .\path5\src

    That is, the path2 and path5 became the TOP folder in zip file. and both bin directories were excluded.

    -x only support path/filename RELATIVE TO THE FINAL PATH IN ZIP FILE. So, if you only want to exclude

    .\path1\path2\bin

    but to include all the other 'bin' directories, the command should be like this:

    7z a -t7z archive.7z .\path1\path2 .\path3\path4\path5 -x!path2\bin

    I tried to use absolute path in -x, but never succeed.