Answers: linux - Finding not empty directories without subdirectories and specific sorting

Sebastian Potasiak

I have a problem with my "homework" on studies.

I have to list all not empty directories from /var and /usr, which do not have subdirectories and their owner is not root user. Also, for each directory I have to show depth in directory tree, i-node number, size, permissions in human-readable and octal formats and absolute path to this directory, and sort it descending by i-node number.

Here is what I've currently done:

find /{us,va}r -type d \! -user root \! -empty -printf "%d %i %k %M %m %u %h/%f\n" | sort -rn

Now I just have to eliminate directories with subdirectories and sort it by i-node number.

So, here comes the questions:

How can I eliminate directories with subdirectories from this list?
How can I sort this list by i-node, which is in the second column?

Thanks for help.

tink

OK, I think I found a python-based solution to your problem.

Save this snippet as e.g. x.py, and chmod +x x.py

#!/usr/bin/python
import sys
x=[]
for line in sys.stdin:
  x.append(line.rstrip())

y=x[:]
for i in x:
  mark=x.index(i)
  for j in y:
    if i.split()[6]  in j.split()[6]  and i != j:
      if i in y: y.remove(i)

for j in y:
  print j

Then pipe your find command (w/o the links bit) through it, and sort

find /{us,va}r -type d \! -user root \! -empty -printf "%d %i %k %M %m %u %h/%f\n" | x.py | sort -k2,2n

Sebastian Potasiak

So, I was right. All I had to do was to add -links 2 argument to find, so it will output directories with only 2 "hard links" (which are not hard links - it's subdirectory counter and every directory has at least 2 subdirs - '.' and '..') and -k 2 to sort, so it will sort by second column.

Whole command looks like this:

find /{us,va}r -links 2 -type d \! -user root \! -empty -printf "%d %i %k %M %m %u %h/%f\n" | sort -rnk 2

command line - How to find the executable files under a certain directory in linux?

linux command-line bash find

HaiYuan Zhang

How to find the executable files under a certain directory in linux?

Related Answers

knittl

use the -executable option:

find <dir> -executable

if you want to find only executable files and not searchable directories, combine with -type f:

find <dir> -executable -type f

EDIT:

checking with the comments i see there’s no type x. i’m sorry, this was my mistake. checking for executable files can be done with -perm (not recommended) or -executable (recommended, as it takes ACL into account).

innaM

Use the find's -perm option. This will find files in the current directory that are either executable by their owner, by group members or by others:

find . -perm /u=x,g=x,o=x

Edit:

I just found another option that is present at least in GNU find 4.4.0:

find . -executable

This should work even better because ACLs are also considered.

AjayKumarBasuthkar

A file marked executable need not be a executable or loadable file or object.

Here is what I use:

find ./ -type f -name "*" -not -name "*.o" -exec sh -c '
    case "$(head -n 1 "$1")" in
      ?ELF*) exit 0;;
      MZ*) exit 0;;
      #!*/ocamlrun*)exit0;;
    esac
exit 1
' sh {} \; -print

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linux - Finding not empty directories without subdirectories and specific sorting