Answers: Microsoft Word 2010 regex replace

timbp

I am having a problem with a regex find and replace in Word 2010 (Windows 7).

I want to convert reference citation numbers in parentheses to the same numbers in brackets. For example, (20-23) should become [20-23], (19, 20) should become [19, 20].

I have the following Find what: \(([0-9], -]*)\) and Replace with: [\1]

But this puts the found expression before the brackets, instead of within. (20-23) becomes 20-23[], (19, 20) becomes 19, 20[]

Can anyone tell me the correct syntax for this replace?

Madball73

The code you pasted had an extra bracket, I'm not sure how it would have done anything but error...

\(([0-9, -]*)\)

works fine.

Sirius_Black

try this

\50(\d+-\d+)\51

replace for [\1]

and tell me if it works

Find matches to regex '[^,] which' in MS Word

microsoft-word regex

JustinJDavies

I wish to Find instances of the substring [^,] which — the word which preceded by a space '' that is preceded by a character that is not a comma [^,]. Can this be done?

The query [,] which works fine but the negation breaks the regex. Is there a special syntax in MS Word or is this not available within the Find/Replace dialogue?

When I try this query I get the Warning dialogue, ^ is not a valid special character for the Find What box or is not supported when the Use Wildcards check box is selected

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Microsoft Word 2010 regex replace