Answers: bash - Shell script error using command find

Anson

My script is supposed to: recursively look for files and directories whose names contain given strings, using find, starting in the current directory. If no arguments are given the message Missing argument(s) shall be printed before returning the error code 1 to the shell.

This is the script:

#!/bin/bash/
if ["${#}" -eq 0]
  then
     echo "Missing argument(s)"
     exit 1
else
  find .  -name "*$@*"
fi

I tried to use this in the terminal, but I got this error: bash: ./myfind: /bin/bash/: bad interpreter : Not a directory

Why? Is my code correct?

Paul Richter

You need to delete the slash at the end of the first line. /bin/bash is the interpreter.

Keith Thompson

You also need a space between [ and ", and between 0 and ].

Bonus: You can simplify "${#}" to just $# - There's no need to quote a variable which is always going to be a number, and there's no need to use braces unless you've got more than just a single variable within the string.

unix - find command exec option

command-line unix bash find

brianegge

I'm trying to use the + option of find exec instead of xargs. However, I can't seem to get it to work. I feel I must be missing something obvious here.

Example:

find . -name "*.java" -exec grep "@author" {} + \;
find: paths must precede expression
Usage: find [-H] [-L] [-P] [path...] [expression]

On the other hand, this works:

find . -name "*.java" -exec grep "@author" {}  \;

as does this:

find . -name "*.java" | xargs  grep "@author"

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bash - Shell script error using command find